560=16t^2-192t

Solution for 560=16t^2-192t equation:

560=16t^2-192t

We move all terms to the left:

560-(16t^2-192t)=0

We get rid of parentheses

-16t^2+192t+560=0

a = -16; b = 192; c = +560;
Δ = b2-4ac
Δ = 1922-4·(-16)·560
Δ = 72704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72704}=\sqrt{1024*71}=\sqrt{1024}*\sqrt{71}=32\sqrt{71}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-32\sqrt{71}}{2*-16}=\frac{-192-32\sqrt{71}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+32\sqrt{71}}{2*-16}=\frac{-192+32\sqrt{71}}{-32}
$